EP proporção
- Created by
- Renato Passos, Eng. de Software
- Reviewed by
- Renato Passos, Eng. de Software
Last updated: Apr 18, 2026
About this calculator
The proportion standard error calculator estimates the variability of a sample proportion relative to the population. It calculates the square root of [p(1−p)] divided by the sample size (n), where p is the observed proportion. This value measures the precision of the estimate and is crucial for surveys, statistical tests, and confidence in sampling results.
The formula √[p(1−p)/n] shows how the variability of a proportion depends on both the proportion itself (p) and the sample size. Proportions near 0 or 1 tend to have lower variability, while larger samples reduce the standard error. For example, in an opinion survey, this calculator shows how reliable a 60% support estimate for a candidate is with a 500-person sample.
It is particularly useful in scenarios like election polls, A/B testing in digital marketing, or quality analysis in production. However, it's essential to ensure the sample is representative and contains at least 10 successes and 10 failures for the formula to be valid. For extreme proportions (0 or 1), the calculator might underestimate actual variability.
An important caution is not to confuse standard error with margin of error. The former measures estimate variability, while the latter includes the standard error multiplied by a confidence factor (e.g., 1.96 for 95% confidence). The calculator is not a substitute for full statistical analysis but serves as a starting point for evaluating sample data reliability.
Frequently asked questions
What is proportion standard error?
It measures how precise a proportion estimate is in a sample. It indicates the expected variability if another sample were taken under the same conditions.
How does sample size affect the calculation?
Larger samples reduce standard error as variability spreads across more observations, making the estimate more reliable.
Why does the proportion p influence the result?
Proportions near 0 or 1 have less natural variability. For example, 90% approval in an opinion poll has less uncertainty than 50%.
Can I use this calculator for small samples?
Not recommended. The formula assumes normal distribution, requiring at least 10 successes and 10 failures in the sample (e.g., n=30, p=60% → 18 successes and 12 failures).
What if the proportion is 0 or 1?
The formula isn't accurate in these cases. Consider alternative methods like Wilson score interval or bootstrapping for extreme proportions.