Espaço Gerado (base?)
- Created by
- Renato Passos, Eng. de Software
- Reviewed by
- Renato Passos, Eng. de Software
Last updated: Apr 18, 2026
Formula
det ≠ 0 ⇒ LI ⇒ base
About this calculator
The generated space calculator checks whether a set of vectors in R^n forms a basis for the subspace they span. It does this by calculating the determinant of the matrix formed by the vectors. If the determinant is nonzero, the vectors are linearly independent (LI) and therefore form a basis for the space they span. Otherwise, they are linearly dependent (LD) and do not form a basis.
The operation is simple: you enter the vectors as rows or columns of a square matrix. The calculator computes the determinant. If det ≠ 0, the vectors are LI and span a subspace of dimension equal to the number of vectors, meaning they form a basis. If det = 0, the vectors are LD and the spanned space has lower dimension. This tool is useful for linear algebra students who need to quickly check linear independence.
Use this calculator when you need to determine whether a set of vectors can serve as a basis for a vector space. For example, when solving coordinate problems, linear transformations, or studying subspaces. It is especially useful in exams or exercises where manual determinant calculation can be tedious. Remember that the matrix must be square (number of vectors equals the dimension of the space).
Cautions: the calculator only works for sets of vectors with the same number of vectors as the dimension of the space (square matrix). If the number of vectors differs from the dimension, the determinant is not defined and the tool cannot be applied directly. Also, note that LI vectors always span a subspace of dimension equal to the number of vectors, but not every spanning set is LI. For infinite-dimensional spaces, this calculator does not apply.
Frequently asked questions
What does it mean if the determinant is nonzero?
It means the vectors are linearly independent and form a basis for the space they span.
Can I use the calculator for vectors with different dimensions?
No, the calculator requires the vectors to have the same dimension and the matrix to be square.
If det = 0, are the vectors always dependent?
Yes, a zero determinant indicates linear dependence, meaning at least one vector is a linear combination of the others.
Does this calculator check if a set spans all of R^n?
Yes, if you have n vectors in R^n and det ≠ 0, they span all of R^n and form a basis.
What if the number of vectors differs from the dimension?
In that case, the determinant concept does not directly apply. You need other methods, such as row reduction.